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2011 NBA Offseason Thread |OT2| The 2K servers are back, baby, they back!
- Thread starter Rodeo Clown
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ryutaro's mama
Member
ph33nix said:
We'd get "OccupyNBA" peeps camping in front of arenas while other patrons stepped over them to go to games.
It would never work 100%.
Although I don't agree with Dwights wording, I kinda agree with the principle. I'm as pissed off as anyone but it's nonsensical to be angry at players for not wanting to play. If an actor took a year off from movies because none of the offers in front of him were good no one would be clamoring that said actor is selfish and owes the fans who pay his salary 2 movies a year. No one would say the same about any other entertainer. But Athletes have to keep working because we have an irrational attachment to our teams?
While I understand that the irrational attachment is the only reason they make millions, they've worked for what they've been paid. Unless you're a season ticket holder or a tv exec that owes the league money with or without a season...having a gripe is kind of crazy.
So we're mad at them for taking away one source of entertainment away from us but readily expect the players to stomach a 1.1 BILLION loss and not complain? Kind of ridiculous, NBA players don't owe us shit.
While I understand that the irrational attachment is the only reason they make millions, they've worked for what they've been paid. Unless you're a season ticket holder or a tv exec that owes the league money with or without a season...having a gripe is kind of crazy.
So we're mad at them for taking away one source of entertainment away from us but readily expect the players to stomach a 1.1 BILLION loss and not complain? Kind of ridiculous, NBA players don't owe us shit.
Boombloxer
Member
*reads*
ItWasMeantToBe19
Banned
The owners want a long deal so the players can renegotiate before the new TV deal is signed. Players want a short deal so they can do so. Might be another lockout in 2017, lol.
ItWasMeantToBe19
Banned
Ken Berger five weeks ago said:
Why did he lie those weeks ago? Why? Why would you do that?
any of you guys know how to do this problem? i haven't been to class in a week 
so i'm kind of lost...
The demand on day t in Clarksville for the newest fad item is given by D(t)=4t^2 - 9e^(0.3t) + 10, for 0<t<15. Find the number of fad items sold in Clarksville in the first two weeks after their release. [Hint: before release, no demand could be met.]
all i know is that it's an antiderivative problem.
so i'm kind of lost...The demand on day t in Clarksville for the newest fad item is given by D(t)=4t^2 - 9e^(0.3t) + 10, for 0<t<15. Find the number of fad items sold in Clarksville in the first two weeks after their release. [Hint: before release, no demand could be met.]
all i know is that it's an antiderivative problem.
MorisUkunRasik
Member
balddemon said:any of you guys know how to do this problem? i haven't been to class in a week
The demand on day t in Clarksville for the newest fad item is given by D(t)=4t^2 - 9e^(0.3t) + 10, for 0<t<15. Find the number of fad items sold in Clarksville in the first two weeks after their release. [Hint: before release, no demand could be met.]
all i know is that it's an antiderivative problem.
balddemon said:any of you guys know how to do this problem? i haven't been to class in a week
The demand on day t in Clarksville for the newest fad item is given by D(t)=4t^2 - 9e^(0.3t) + 10, for 0<t<15. Find the number of fad items sold in Clarksville in the first two weeks after their release. [Hint: before release, no demand could be met.]
all i know is that it's an antiderivative problem.
Odds this is what they really talk about in the NBA lockout negotiations: 8-1
Jamesfrom818
Banned
etiolate said:
It must be why Whynotbrook had his backpack. He was doing homework while the adults were talking.
ItWasMeantToBe19
Banned
balddemon said:any of you guys know how to do this problem? i haven't been to class in a week
The demand on day t in Clarksville for the newest fad item is given by D(t)=4t^2 - 9e^(0.3t) + 10, for 0<t<15. Find the number of fad items sold in Clarksville in the first two weeks after their release. [Hint: before release, no demand could be met.]
all i know is that it's an antiderivative problem.
Demand is a slope, derivatives are slopes, since it's asking you to find the equation for the total from the equation for the slope, that makes it an antiderivative (anti or opposite of turning an equation for a number into an equation for a slope), that is important to know. Now that you understand better why it's an antiderivative, just do the standard calculations for finding antiderivatives using t^number=[t^number+1]/[number+1]. Remember that this also applies to numbers that have no variables. The antiderivative of 10 is 10t.. Also, that question is phrased like shit, it wants you to have t=15 but asks you to find total after two weeks which sane people say is 14 days. At least I'm pretty sure that's how it goes, haven't done Calculus in a while, hope I don't screw you up.
Ninja Scooter
Member
Duki said:
Black Mamba
Member
balddemon said:any of you guys know how to do this problem? i haven't been to class in a week
The demand on day t in Clarksville for the newest fad item is given by D(t)=4t^2 - 9e^(0.3t) + 10, for 0<t<15. Find the number of fad items sold in Clarksville in the first two weeks after their release. [Hint: before release, no demand could be met.]
all i know is that it's an antiderivative problem.
The integral is (4/3)t^3 - 30e^(.3t)+10t
Remember that the integral of e is e, so you just have to divide the coefficient of e by the coefficient of t in the exponent (U substitution).
you can do the rest.
^^ thanks man. the rule with e was definitely confusing me.
so what you're saying is....
1. antiderivative
2. t=14
3. answer?
and if so, the question makes since because the < are supposed to be less than or equal to, but the hint says you can't have demand on day 0. because day 1 is when it gets released. so t=14
thanks for clarifying that.
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i hate business calc so much. i can do most math pretty easily, but throw words in there and i get totally lost.
ItWasMeantToBe19 said:
so what you're saying is....
1. antiderivative
2. t=14
3. answer?
and if so, the question makes since because the < are supposed to be less than or equal to, but the hint says you can't have demand on day 0. because day 1 is when it gets released. so t=14
thanks for clarifying that.
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i hate business calc so much. i can do most math pretty easily, but throw words in there and i get totally lost.
ItWasMeantToBe19
Banned
No, t/time is equal to 15 in that equation, it's phrased like shit and is misleading to make you believe it's 14. When it tells you that 0<t<15, that means it wants you to put in 15 for T. Punch in the numbers into the integral and you'll find that t=15 comes up with a clean, neat solution, whereas t=14 is way more messy which basically confirms that the question is asking about t at 15.
Or maybe that's just me and I ended up confusing you, ehh.
Or maybe that's just me and I ended up confusing you, ehh.
Black Mamba
Member
ItWasMeantToBe19 said:
I thought it was 14. He has to measure the amount of sold from day 0 to 14. He's finding the sum under the function from 0 to 14.
It's not clean with 14 or 15, anyway. Unless I integrated incorrectly.
edit: ahh, unless they count day 1 as the first day of sales and then day 15 as the 14th.
In that case, you do measure from 1-15, no?
Think you plug in 15 and then 1 and subtract em off the integral. Actually, pretty sure this is right.
ItWasMeantToBe19
Banned
It's pretty clean with t=15 if you drop the .017 off of the answer for e^(.3x15). F(15)-F(0) comes to
unless I've forgotten a lot of Calculus 
1950
Black Mamba
Member
ItWasMeantToBe19 said:It's pretty clean with t=15 if you drop the .017 off of the answer for e^(.3x15). F(15)-F(0) comes tounless I've forgotten a lot of Calculus1950
But you can't do it from 15 to 0. You have to do it to 1. If you drew the curve and shaded what is being summed, it's from T = 1 to T = 15.
no?
no. You can't do 15-1. You have to measure T at 15 and T at 1. You're summing under a non linear function.
actually, now I'm confused. Since day = 0 to day = 1 cannot be met, I think you ignore it. Basically, there's no curve there.
ItWasMeantToBe19
Banned
Since 0 and 15 are directly there in the equation and my answer looks good, I am going to take my clean solution and go home like old-school nerds who may not be as smart as they thought they were.
Black Mamba said:
so plug in 15 (to the integrated function), plug in 1 (to the integrated function), subtract what i get, and that's the answer. i should have done this earlier, like 6 hours earlier, then maybe it would have been easier to understand...for all of us..i'll just ask my teacher for help tomorrow if we're wrong lol. thanks and good night ya'll
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ItWasMeantToBe19
Banned
In F(15) - F(1), you're left with a sixth of a unit.
Shit doesn't look right in an equation that's asking about specific number of units sold
I probably shouldn't do calculus after midnight though.
Shit doesn't look right in an equation that's asking about specific number of units sold
I probably shouldn't do calculus after midnight though.
Black Mamba
Member
balddemon said:
Something isn't right. The 0-1 plot is screwing up the equation. Plug in t = 2 and you still get a negative answer because 0-1 is a big negative number.
ItWasMeantToBe19
Banned
I think the market demand of a unit can technically be negative in extreme circumstances, but I think you may be overthinking it, Mamba, and the instructor was just making a word problem for F(15)-F(0) with f(t)=4t^2 - 9e^(0.3t) + 10 without going over all points in the equation.
Black Mamba
Member
Are we sure this is an integral problem?
You just plug 15 into the Demand equation. The answer is 100.
"The demand on day t in Clarksville for the newest fad item is given by D(t)=4t^2 - 9e^(0.3t) + 10, for 0<t<1."
"Find the number of fad items sold in Clarksville in the first two weeks after their release. [Hint: before release, no demand could be met.]"
The amount of an item sold is the each day. You add up each point t. this is a standard summation equation.
Take the demand curve, sum from t = 1 to t =15. No?
You just plug 15 into the Demand equation. The answer is 100.
"The demand on day t in Clarksville for the newest fad item is given by D(t)=4t^2 - 9e^(0.3t) + 10, for 0<t<1."
"Find the number of fad items sold in Clarksville in the first two weeks after their release. [Hint: before release, no demand could be met.]"
The amount of an item sold is the each day. You add up each point t. this is a standard summation equation.
Take the demand curve, sum from t = 1 to t =15. No?
ItWasMeantToBe19
Banned
I'm pretty sure that a demand curve is a slope (therefore a derivative) that can't show total demand and that the normal equation for finding total demand is the equation you put the numbers into and since demand is the slope of total demand (at various times or prices), total demand is an antiderivative of demand and demand is a derivative of total demand.
Finally going to bed, please don't ban me or Mamba, Blackace, I love math and don't use it as much now...though I should use it at not midnight.
Finally going to bed, please don't ban me or Mamba, Blackace, I love math and don't use it as much now...though I should use it at not midnight.
Black Mamba
Member
ItWasMeantToBe19 said:
er, I think I know the problem. So long since I've had to do an economic problem.
D(t) is not the right equation to integrate. Normally, Demand is graphically represented as Price as a function of quantity. In this case the, T is on the Y axis of the curve, not X. We're integrating the wrong equation.
Have to re-write the equation in terms of T(x) just like the Demand curve is P(x) when we graph it. Hence the weird negative numbers.
I am way too lazy to re-write the equation. Once you do that, then you integrate.
or I could be overthinking it. But I do remember whenever we got D(p) = something, we had to convert it to P(x).
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