• Hey Guest. Check out your NeoGAF Wrapped 2025 results here!

The Math Help Thread

Status
Not open for further replies.
Thank you so much! So "distribution" means to show the probabilities associated with each desired outcome, and then sum up all of the probabilities of the desired outcomes, more or less? Because 1/6 is the sum of the probabilities of each combination that gets you |X-Y| = 0.


That is correct. In this case, all the data is discrete, die only roll single numbers, but a distribution could also be continuous, these are called probability distributions (http://en.wikipedia.org/wiki/Probability_distribution) and are simply functions.

So the distribution seen here is a function of Z say, f(Z) = Probability of rolling an outcome (|X-Y| = Z).

Glad that I could help :)
 
Glad that I could help :)
Your monkey math is most marvelous.


Empathizing with Cantor's insanity and doing a survey of transcendentals, I happened across schizophrenic numbers. Never heard of those crazy digits before. I was looking at the recursive function f(n)= 10*f(n-1)+n ; f(0)=0 just to explore these numbers a bit. The square-root of the odd terms has these interesting strings of numbers, the same sequence of repetitions but varying in length, odd-term to odd-term. Anyway I just happened to be resizing a window and saw this triangle pop-out:
schizonumqouxp.png

Not a whole lot on these but I hadn't seen this property mentioned (if it is consistent, I saw it in the 7-9 odd-values I looked at), numeric novelty.

edit: (day late, I see the function was incorrectly put in... its fixed)
 
Hey MathGAF, I have a test in a couple of hours and I can't figure out this question:
Is the following series convergent or divergent:

(from n=1 to infinity) ∑(-1)^n * ln(n)

This is where I am so foar:

|(-1)^n * ln(n)| = ln(n)

ln(n) > 1/ln(n) > 1/n

Since 1/n is a divergent harmonic series, so is 1/ln(n) by comparison and so is ln(n) by comparison.

The answer should be divergent, but not to (infinity) or -(infinity). How am I supposed to solve this? :(
 
I think I got it. By the test of divergence (I = infinity):

An = ∑(-1)^n * ln(n)
Lim (n->I) ∑|(-1)^n * ln(n)| = Lim (n->I) |ln(n)| = Infinity

So the series in divergent. But because the original series = ∑(-1)^n * ln(n), it alsternates from beeing divergent to I and divergent to -I, and therefor the answer is that it's divergent, but not to I or -I.

Edit: Converging to infinity doesn't exist ;)
 
Which is why I put it in quotation marks, since at times people include infinity in their definition of convergence, as stupid as it may seem.

Also you do not prove that it doesn't "converge" to I (or -I). Just because a series is alternating doesn't mean it can't converge. Quite frankly it still seems at first glance (unless I missed something) that your series "converges" to infinity.

Ah, I see. Well I think that ln(n) converges to I, and -ln (n) converges to -I. And because the series is multiplied by (-1)^n, it alternates from converging to infinity to converging to -infinity. I wouldn't know how to explain it otherwise :(
 
Wow that's a terrific explanation! I get why it converges now. But from that explanation, I'd conclude that it converges to infinity.

But the answer should be that the series is divergent, but neither to infinity or -infinity. I can't conclude that just yet.
 
I think I got it. By the test of divergence (I = infinity):

An = ∑(-1)^n * ln(n)
Lim (n->I) ∑|(-1)^n * ln(n)| = Lim (n->I) |ln(n)| = Infinity

So the series in divergent. But because the original series = ∑(-1)^n * ln(n), it alsternates from beeing divergent to I and divergent to -I, and therefor the answer is that it's divergent, but not to I or -I.

Edit: Converging to infinity doesn't exist ;)

You're wrongly applying the test here. The absolute sign is as far as I know not part of the divergence test. You must take into account the -1 term.

If you generalize the series, akin to what ElTopo did, you get the following series without the (-1)^n term:

∑(-1)^n * ln(n) = ∑ln(2n)-ln(2n-1) = -∑ln(1-1/2n)

And:
lim(n->infty) ln(1-1/2n) = 0

Since it is zero, it is inconclusive whether the sum of this series either converges or diverges. But ElTopo's analysis shows that the sum is divergent.
 
This should be a simple problem for someone to help me figure out since it is not complicated or anything since it is just from College Algebra.

((3a-8)/(a^2-5a+6))+((a+2)/(a^2-6a+8))

Getting the denominators to be the same is really throwing me off.
 
This should be a simple problem for someone to help me figure out since it is not complicated or anything since it is just from College Algebra.

((3a-8)/(a^2-5a+6))+((a+2)/(a^2-6a+8))

Getting the denominators to be the same is really throwing me off.

Factor out the denominators to (a-3)(a-2) and (a-4)(a-2). I'm a little rusty, but is there something I'm not seeing?
 
Factor out the denominators to (a-3)(a-2) and (a-4)(a-2). I'm a little rusty, but is there something I'm not seeing?

Well, I got that part down, it is just what to do after that. I am pretty sure I have to multiply 3a-8/((a-3)(a-2)) by (a-4) and a-2/((a-4)(a-2)) by (a-3). I ended up with 4a^2-25a+38/((a-2)(a-3)(a-4)). I am not sure what I am supposed to do with the numerator to simplify it. I think I am supposed to factor it out but I cannot figure out how to do it.
 
Well, I got that part down, it is just what to do after that. I am pretty sure I have to multiply 3a-8/((a-3)(a-2)) by (a-4) and a-2/((a-4)(a-2)) by (a-3). I ended up with 4a^2-25a+38/((a-2)(a-3)(a-4)). I am not sure what I am supposed to do with the numerator to simplify it. I think I am supposed to factor it out but I cannot figure out how to do it.

You added the numerators incorrectly. The answer you get should be 4a^2+21a+26. Then you would factor it to (a-2)(4a-13).
 
big ander, thanks for your help dude. you were totally right about my missing variable and anything. haha. genius!!! i have another factoring question. FACTORING!!

(x-4)^2 - (x-7)^2

"perform indicated operations and simplify completely"

this section is about "factoring special forms" or something..

so, i'm looking at it. both of those terms are squares, correct?

so i'm thinking a^2 - b^2 = (a+b)(a-b). is that right?

so is (x-4) + (x-7) times (x-4) - (x-7) correct? is that factored all the way?
 
big ander, thanks for your help dude. you were totally right about my missing variable and anything. haha. genius!!! i have another factoring question. FACTORING!!

(x-4)^2 - (x-7)^2

"perform indicated operations and simplify completely"

this section is about "factoring special forms" or something..

so, i'm looking at it. both of those terms are squares, correct?

so i'm thinking a^2 - b^2 = (a+b)(a-b). is that right?

so is (x-4) + (x-7) times (x-4) - (x-7) correct? is that factored all the way?

Yeah but simplify [(x-4)+(x-7)] and [(x-4)-(x-7)]
 
I have a chem E question for the people on here...I think I've got it down but I'm not so sure.

So there is a tube filled with water:

_____________________
Source =>
C_in ---------------> C_out
_____________________

There is a solute dissolved in it. On the left, the concentration is 1 mg/L H20. On the right, the concentration is 21 mg/L.

There is a 50 mg source of solute added at the input end of the tube over a period of 10 minutes (5 mg/min). The system is in steady state and mixes as solute is added. I am to find the volumetric flow rate in L/sec through the tube.

So What I did was start out with a mass balance.

So I have the concentrations, and I can multiply these by the volume in the tube to get the total solute. I also have the source, which I'll take as 50.

So V*C_in+Source-V*C_out = 0, so V = Source/(C_out-C_in) = 50/(21-1) = 2.5 L

So here's where I get stuck. I have the volume I need for the flow rate, but now I need time. The only time I really have is the rate of adding the source, but I don't think that's related, so I decided to divide by the total amount of time emitted.

So 2.5 L/10 min = .25 L/min

This doesn't really make sense to me, though, because This would imply that adding the source at different rates would affect the blood flow. That seems silly, honestly, so I know I went wrong somewhere. Anyone see any problems?
 
I have a chem E question for the people on here...I think I've got it down but I'm not so sure.

So there is a tube filled with water:

_____________________
Source =>
C_in ---------------> C_out
_____________________

There is a solute dissolved in it. On the left, the concentration is 1 mg/L H20. On the right, the concentration is 21 mg/L.

There is a 50 mg source of solute added at the input end of the tube over a period of 10 minutes (5 mg/min). The system is in steady state and mixes as solute is added. I am to find the volumetric flow rate in L/sec through the tube.

So What I did was start out with a mass balance.

So I have the concentrations, and I can multiply these by the volume in the tube to get the total solute. I also have the source, which I'll take as 50.

So V*C_in+Source-V*C_out = 0, so V = Source/(C_out-C_in) = 50/(21-1) = 2.5 L

So here's where I get stuck. I have the volume I need for the flow rate, but now I need time. The only time I really have is the rate of adding the source, but I don't think that's related, so I decided to divide by the total amount of time emitted.

So 2.5 L/10 min = .25 L/min

This doesn't really make sense to me, though, because This would imply that adding the source at different rates would affect the blood flow. That seems silly, honestly, so I know I went wrong somewhere. Anyone see any problems?
Assuming the solutions are "well mixed", this might be a Diffy Q question with e^cx as a base solution. This is a memory from literally eight years ago, but I remember this sort of question...

Anyway, I have nothing more of value to offer here. To my kitchen!
 
I have a chem E question for the people on here...I think I've got it down but I'm not so sure.

So there is a tube filled with water:

_____________________
Source =>
C_in ---------------> C_out
_____________________

There is a solute dissolved in it. On the left, the concentration is 1 mg/L H20. On the right, the concentration is 21 mg/L.

There is a 50 mg source of solute added at the input end of the tube over a period of 10 minutes (5 mg/min). The system is in steady state and mixes as solute is added. I am to find the volumetric flow rate in L/sec through the tube.

So What I did was start out with a mass balance.

So I have the concentrations, and I can multiply these by the volume in the tube to get the total solute. I also have the source, which I'll take as 50.

So V*C_in+Source-V*C_out = 0, so V = Source/(C_out-C_in) = 50/(21-1) = 2.5 L

So here's where I get stuck. I have the volume I need for the flow rate, but now I need time. The only time I really have is the rate of adding the source, but I don't think that's related, so I decided to divide by the total amount of time emitted.

So 2.5 L/10 min = .25 L/min

This doesn't really make sense to me, though, because This would imply that adding the source at different rates would affect the blood flow. That seems silly, honestly, so I know I went wrong somewhere. Anyone see any problems?
I came across these notes, just browsing out of interest and thought they might help:
b. Continuous steady-state process

Let us consider a continuous mixer which has two input streams and, of course, one
output stream (See Figure 6 for a diagram). Suppose the first input stream has a flow rate of
10000 lb/hr of a 40 wt. % solution of salt in water while the second input stream has a flow rate
of 20000 lb/hr of a 70 wt. % solution of salt in water. What is the flow rate and composition of
the output stream?

Since the system is now characterized in terms of rates of flow into the control volume
(additions) and rates of flow out of the system (withdrawals), we need to restate the principle of
conservation of mass as follows:
(I-2) Rate of change of holdup =
rate of additions to the control volume
- rate of withdrawals from the control volume
For a continuous system operating in the steady state, the holdup does not change with time.

Therefore, the rate of change of holdup is zero and Eqn. I-2 becomes
(I-3) Rate of withdrawals from the control volume =
Rate of additions to the control volume
Let us apply this to the mixer problem. The control volume is the contents of the mixer (even
though these do change) and the basis is the total rate of flow to the mixer. As in the previous
example, the conserved species are salt and water.

Salt
F
in
F
out
z

Rate of withdrawal of salt =
rate of additions of salt to the mixer
Rate of additions = (10000)(0.4) + (20000)(0.7)
= 18000 lb/hr of salt
Water
Rate of withdrawal of water =
rate of additions of water to the mixer
Rate of additions = (10000)(0.6) + (20000)(0.3)
= 12000 lb/hr

Thus the stream leaving the mixer has a flow rate of 18000 lb/hr of salt and 12000 lb/hr of water,
for a total of 30000 lb/hr. This is exactly the total flow rate of the mixer output we get by adding
up the total flow rates to the mixer. Also, the composition of salt of the stream leaving the mixer
=
(100)(18000)/(30000) = 60 wt %.
{pages 12-13}
...and I found this interesting:
Today, using process simulation program such as PRO-II, ASPEN, and HYSIM, a single engineer can solve significant flow
sheeting problems in as little as a day or two and, moreover, do it much more accurately and in much more detail than
was previously possible.

The process engineer can now concentrate on the process model and the results rather than concocting a
scheme to solve the model equations themselves. The simulation program will do that, at least
most of the time. However, things do go wrong at times. Either the problem is very difficult for
the simulator to solve or a mistake has been made in describing the process to the program. Thus,
in order to fix what is wrong, the engineer does need to know something about how the simulation
program attempts to solve the problem.
{Pages 3-4}
 
yixvGIC.png


So obviously A = (5,8) and B = (2,4).

However, we have so far only worked in the basis originating from origin, so I'm not sure how to express that vector. I only know how to express a vector given its ending coordinates when starting in origin, so if a vector ended in (5,8) I'd put that as:
(5)
(8)

Any hints here?

EDIT: NVM, solved!
 
The limit of f(x) as x approaches 2 is 2.

This is not true unless f(x) = x
Edit- was wrong here, many can give an answer of 2, such as f(x) = -x^2 +6. But you really need to know what f(x) is
You can't assume this is true, f(x) can be many things.
 
This is not true unless f(x) = x
You can't assume this is true, f(x) can be many things.

They have a picture of it's graph.
If it isn't 2 then I don't know what else it could.

The chapter is about limit laws, so I think I'm pretty much supposed to assume that it's 2.
The real issue here is how to apply that to the new function I listed.
 
Can you post the graph or the equation they use? Without actually knowing the question and what f(x) is, its impossible to answer.

I don't think it actually matters. They didn't even provide the equation or anything.
I think that the point of the exercise is to just check if I can manipulate the limit laws correctly, that is all I'm trying to accomplish.
 
Do they not provide an equation? And it it's just a graph can you come up an equation?

So they flat out state that the limit of f(x) as x approaches 2 is 2?

Your notation is what is confusing me.
If you mean something like

g(x) = [(x^3)f(x)] then yes the limit of g(x) is 16 since you end up with (2^3)(2) = 16
I was thinking for some reason you meant f(x) = (x^3)f(x) because that would be completely different.
 
They didn't explicitly tell me what the limit is, but from looking at the graph it's rather obvious what they want me to think that it is.

No equation is given and there's no way I can come up with one. I honestly don't think one is required for what they are asking me to do.
 
Yeah the rules for limit manipulation are pretty nice.
If lim f(x) = A when x ->y and lim g(x) = B when x ->y then the following are true.
(all for when x -> y)
lim f(x) + g(x) = A + B , lim f(x) - g(x) = A - B
and
lim f(x)g(x) = AB , lim f(x)/g(x) = A / B

So as Therion stated, you know that lim f(x) = 2, and if g(x) = x^3 then lim g(x) = 8.
So according to the rules, lim f(x)g(x) = 2*8 = 16
 
Got another one for you fellows. Sorry if this is annoying, I'm just not that confident. I'll probably be in here a lot tonight.

Have I evaluated this correctly?

UzKlKGo.jpg
 
Got another one for you fellows. Sorry if this is annoying, I'm just not that confident. I'll probably be in here a lot tonight.

Have I evaluated this correctly?

UzKlKGo.jpg

Yes, but why did you push the limits into the square root? That's really not necessary to solve the equation.
 
Now I've got another one.

SVN7MaW.png



After I simplified it the denominator will still be zero.
That means that the limit does not exist? I don't see what else I could do with it.
 
Correct, the limit doesn't exist.

Do you understand why? For the limit to exist, you have to get the same answer when approaching from the right and the left sides. If you are approaching from the left, your equation tends to positive infinity, but when you approach from the right, it tends to negative infinity.
 
Correct, the limit doesn't exist.

Do you understand why? For the limit to exist, you have to get the same answer when approaching from the right and the left sides. If you are approaching from the left, your equation tends to positive infinity, but when you approach from the right, it tends to negative infinity.

I just assumed that the limit didn't exist because the function is in an indeterminate form for x approaching -1.

I can't really picture it in my head without graphing it out so I don't know anything beyond that.
 
I just assumed that the limit didn't exist because the function is in an indeterminate form for x approaching -1.

I can't really picture it in my head without graphing it out so I don't know anything beyond that.

The way to see this without a graph is to plug in numbers very close to -1, the point at which the limit does not exist. You can do this from each side, to see the one sided limit.

For example, for x / (x + 1), if approaching from the left, put in numbers that go closer and closer to -1 from the left.

plug in x = -1.01, you get 101
plug in x = -1.001, you get 1001
plug in x = -1.000001, you get 10^6

So as you can see, getting closer and closer to -1 from the left makes the numbers larger and larger, meaning the left handed limit will tend to positive infinity.

If you wanted to see the right handed limit, plug in numbers coming from right.

plug in x = -0.99 , you get -99
plug in x = -0.9999, you get -9999
plug in x = -0.99999999, you get -10^8

As you can see, when approaching this function from the right, the numbers tend to negative infinity, so the limit from the right hand side is negative infinity.
 
Was looking over my old Calculus I textbook and found this problem that I just can't solve.

Fat City occupies a circular area 10 miles in diameter and contains 500,000 inhabitants. If the population now is growing at a rate of 20,000 inhabitants a year, how fast should the diameter be increasing now in order to maintain the circular shape and the same population density (= number of people per square mile)? If the population continues to grow at a rate of 20,000 per year, how fast should the diameter be increasing in 5 years?

The answers in the back of the book are 0.2 and ~0.18, respectively. I know this is a problem involving the chain rule and that (dp/dt)=20,000, area = (pi)r^2, and radius = 5. But I am stuck there. I am at a loss at how the answers are 0.2 and ~0.18, respectively.
 
Embarrassing algebra help edition!

Where do I go from here?

zirwYve.png



I know that's hard to read. This stuff isn't easy to type on here though.
The original function is

zdBOiBn.png


And I simplified it down to this

dcp3222.png


Don't know what to do with it after that.
I expanded the stuff in the denominator and factored out an h^2 in the numerator, but that didn't really get me anywhere.
 
Was looking over my old Calculus I textbook and found this problem that I just can't solve.



The answers in the back of the book are 0.2 and ~0.18, respectively. I know this is a problem involving the chain rule and that (dp/dt)=20,000, area = (pi)r^2, and radius = 5. But I am stuck there. I am at a loss at how the answers are 0.2 and ~0.18, respectively.

The hardest parts of these are making the equations.
We know that dP/dt = 20000, and a = (pi)r^2 like you said. Now note that we have a relationship between P and a, specifically
P/a = 500,000 / (pi)5^2
Rearranging this equation gives a = (P (pi) 5^2 / 500000)
we can take the derivative w.r.t time here and we get...

da/dt = dP/dt ( (pi)5^2 / 500000) and we can plug in dP/dt, which was 20,000.
This tells us that da/dt = pi after calculating the above.

Now we need another equation with da/dt, but we do know the area equation, so we can take the derivative of it.

a = (pi) r^2 Take the derivative (Here is where the chain rule comes in)
da/dt = 2(pi)r (dr/dt), and we know r is 5.

Now combine both equations and we get (pi) = 2 (pi) (r) dr/dt
rearranging gives dr/dt = 1/2*r which is 0.1 when we plug in the r = 5.
Since the question asks for change of diameter, and we have change of radius, we just multiply by 2. This gives the answer of 0.2.

For the part about 5 years later, we need the new radius.
The new population is P`= 500,000 + 20,000 *5 = 600,000
Since we know that Population / area is a constant, we can use
500,000/(pi)5^2 = 600,000/(pi)r^2 The left side is the ratio from 5 years ago, where we knew the population was 500,000 and radius was 5. The right side is the new population of 600,000. Solving for r gives r = sqrt(30)

Using the relationship we already found, dr/dt = 1/(2r) we plus in the new r and see that the change of radius 5 years later is 0.091ish, so multiplying by 2 for the diameter gives the .18
 
Don't know what to do with it after that.
I expanded the stuff in the denominator and factored out an h^2 in the numerator, but that didn't really get me anywhere.

when doing the algebra, its much easier to try and combine the fractions as soon as possible. The end result should be:

(-2hx - h^2) / ((x^2)(x+h)^2) and this is all divided by h. We can factor out an h from the top to cancle with this h to finally get

(-2x - h)/ ((x^2)(x + h)^2)

Now i'm assuming you wrote the question wrong because it should be h ->0, not x, correct? Because the entire purpose of examples like this is to finally cancle out that bottom h.

So now since we did do that, we can plug in h = 0 and get -2/x^3
 
Alright, one last one before finally moving onto German homework.


wl7Opa6.png



The text says "From the graph of g, state the intervals on which g is continuous."

A couple things -

Can infinity count as part of continuity?
How do I state the intervals of continuity when I can only see where it is not continuous? (such as at -2, 2, 6, and 8)
 
Oh wow, forgot all about my friend, the glorious open bracket.

Forgetting notation can really mess with your head.
It's almost 4 in the morning, that's my excuse.

Thanks!
 
The hardest parts of these are making the equations.
We know that dP/dt = 20000, and a = (pi)r^2 like you said. Now note that we have a relationship between P and a, specifically
P/a = 500,000 / (pi)5^2
Rearranging this equation gives a = (P (pi) 5^2 / 500000)
we can take the derivative w.r.t time here and we get...

da/dt = dP/dt ( (pi)5^2 / 500000) and we can plug in dP/dt, which was 20,000.
This tells us that da/dt = pi after calculating the above.

Now we need another equation with da/dt, but we do know the area equation, so we can take the derivative of it.

a = (pi) r^2 Take the derivative (Here is where the chain rule comes in)
da/dt = 2(pi)r (dr/dt), and we know r is 5.

Now combine both equations and we get (pi) = 2 (pi) (r) dr/dt
rearranging gives dr/dt = 1/2*r which is 0.1 when we plug in the r = 5.
Since the question asks for change of diameter, and we have change of radius, we just multiply by 2. This gives the answer of 0.2.

For the part about 5 years later, we need the new radius.
The new population is P`= 500,000 + 20,000 *5 = 600,000
Since we know that Population / area is a constant, we can use
500,000/(pi)5^2 = 600,000/(pi)r^2 The left side is the ratio from 5 years ago, where we knew the population was 500,000 and radius was 5. The right side is the new population of 600,000. Solving for r gives r = sqrt(30)

Using the relationship we already found, dr/dt = 1/(2r) we plus in the new r and see that the change of radius 5 years later is 0.091ish, so multiplying by 2 for the diameter gives the .18

Thanks, man. Not figuring out that problem was annoying. I see that my mistake was not seeing the relation P/a = 500,000 / (pi)5^2.
 
Hey gaf, got a calc assignment and one of the problems is really bothering me.

A vacant plot of land is situated at the corner of two streets which intersect at right angles. A tree stands in the plot 64 feet from one street and 27 feet from the other. What is the shortest possible length of a path cutting across the corner of the plot and passing by the tree?
 
Hey gaf, got a calc assignment and one of the problems is really bothering me.

A vacant plot of land is situated at the corner of two streets which intersect at right angles. A tree stands in the plot 64 feet from one street and 27 feet from the other. What is the shortest possible length of a path cutting across the corner of the plot and passing by the tree?
Isn't this just a straight line from the street corner to the tree? or am I missing something?
 
Hey gaf, got a calc assignment and one of the problems is really bothering me.

A vacant plot of land is situated at the corner of two streets which intersect at right angles. A tree stands in the plot 64 feet from one street and 27 feet from the other. What is the shortest possible length of a path cutting across the corner of the plot and passing by the tree?

It's an optimization problem. You'll be doing plenty of them in calculus.

4w6a04C.png


I actually can't do this one by hand ... it's been a long time haha. The y variable should be the diagonal length of the path, 'cause that's what you're trying to minimize. But I'm not sure what to pick as the x variable to make the equation as simple as possible. Anyways, I got the answer using computer software and it really is 125.
 
treeeee3nkjw.png

This does not discount the existence of a gate.

edit: p(36)= 125
edit: it should also be d/(dx) L(x)=0 => roots. That notation shit wouldda kept me up all night... drinking thinking about it.
 
Usually when doing these optimization questions you know an equation and want to find the derivative and set it to 0. For this example, we know the Pythagoras equation h^2=a^2 + b^2. Now the problem is finding a relationship between a and b so we can take the derivative.
For this question we can use the equation of a line, passing through the point (27,64), the point of the tree.
Here's my work:
PJrzp8Jl.jpg


Sorry it's kinda messy and blurry but you should get the idea from it.
 
Status
Not open for further replies.
Top Bottom